geometry class work i need help please 13

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Given:  Triangle  ABC with AD/DB = CE/EB  

Prove:  LINE DE || LINE AC                                  

What is the missing step in the proof number 8?

1. AD/DB = CE/EB ———->   given

2.AD/DB+1 = CE/EB+1 ——–>  Addition Property of Equality

3.AD+DB/DB =CE+EB/EB —————> using common denominators

4. AB = AD + DB
 CB = CE + EB  ———-> segment addition

5.AB/DB =CB/EB ——>  Substitution Property of Equality

6.angle ABC congruent to angle DBE ————>  Reflexive Property of Congruence

7.triangle ABC ~ triangle DBE ———-> SAS similarity criterion

8.  MISSING PROOF?     ——— > Corresponding angles of similar triangles are congruent.

9.LINE DE
|| LINE AC  —————————-> If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel.

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